Answer:
x=1 and y = 9
Explanation:
Solving using elimination method:
In elimination method we solve equations such that one variable cancels out and we find the value of other variable.
x + 7y = 64
x + 3y = 28
Subtracting both equations:
x + 7y = 64
x + 3y = 28
- - -
___________
0 +4y = 36
y= 36/4
y=9
Putting value of y in one of the equation,
x+7y = 64
x + 7(9) = 64
x + 63 = 64
x = 64-63
x = 1
So, x=1 and y=9
Solving using substitution method:
In substitution method, we substitute value of one variable into other value
x + 7y = 64 (1)
x + 3y = 28 (2)
From 1
x = 64 -7y
Putting value of x in eq(2)
(64 -7y) + 3y = 28
64 -7y +3y =28
64 - 4y = 28
-4y = 28 -64
-4y = -36
y = -36/-4
y = 9
Putting value of y in eq (1)
x + 7y = 64
x + 7(9) = 64
x + 63 = 64
x = 64 - 63
x = 1
So, x=1 and y = 9.