Question

`x^2+3=3-x`
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Answer 1

The answer should be x = [0, -1]

Answer 2

x= 0 and x = -1

Explanation:

Solving the equation:

`x^2 +3 = 3-x`

Adding -3 on both sides

`x^2 +3-3 = 3-3-x`

`x^2  = -x`

Rarranging

`x^2 +x= 0`

Solving quadratic equation using quadratic formula

`x=(-b\pm√(b^2-4ac))/(2a)`

where a = 1 , b =1, c= 0

`x=(-1\pm√((1)^2-4(1)(0)))/(2(1))\\x=(-1\pm√(1-0))/(2)\\x=(-1\pm√(1))/(2)\\x=(-1\pm1)/(2)\\x = (-1+1)/(2) \,\,and\,\, x=(-1-1)/(2)\\x=  (0)/(2) \,\,and\,\,  x=(-2)/(2)\\x=0 \,\,and\,\, x= -1`

So, x= 0 and x = -1