Question

X^y=p

Express in logarithmic form for the base.

Answer 1

`y= log_(x)(p)`

Step-by-step explanation

The given expression is

`{x}^(y) = p`

We take logarithm of both sides to base x.

`log_(x)( {x}^(y) ) = log_(x)(p)`

Apply the power rule of logarithms to get:

`ylog_(x)( {x}) = log_(x)(p)`

Logarithm of the base is 1.

This implies that,

`y( 1) = log_(x)(p)`

`y= log_(x)(p)`