Question

Please help me. I'm so desperate not even my group chat is helping​

Answer 1

The distance from Martin's place to the school (a) is 5 units, determined using the Pythagorean theorem with given values of 12 units from the school to Haley's place (b) and 13 units between Haley's and Martin's places (c).

Distance from the school to Haley's place (b): 12

Distance between Haley's place and Martin's place (c): 13

Using the Pythagorean theorem:

c^2 = a^2 + b^2

Substitute the given values:

13^2 = a^2 + 12^2

Simplify the equation:

169 = a^2 + 144

Subtract 144 from both sides:

25 = a^2

Take the square root of both sides:

a = √25

Simplify:

a = 5

Therefore, the distance from Martin's place to the school (a) is 5 units.

Answer 2

5 between Martin's place and the school

Explanation:

I don't know if you can draw a diagram from by directions, but you can try. It will help you to see the problem.

Draw

Draw a line that looks like this on your paper.

<===============:

school X Martin's place

Now draw a line going upwards from the arrow head.

∧ Haley's place.

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<=============:

school x Martin's place

Label the distance from the school to Haley's place as 12

I can't draw a line between martin's place and Haley's but you can. Label it as 13

So the givens are

c = distance between Haley's place and Martin's = 13

b= distance from the school to Haley's is 12

a = ? Distance from Martin't and the school = x

Formula

c^2 = a^2 + b^2

Solution

13^2 = 12^2 + a^2

169 = 144 + a^2 Subtract 144 from both sides.

169 - 144 = 144 - 144 + a^2

25 = a^2

sqrt(25) = sqrt(a^2)

a = 5