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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

The moose population in a New England forest can be modeled by the function.

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! The moose population in a New England-example-1
User Tyh
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2 Answers

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The answer is A: y=96 The maximum number of moose that the forest can sustain at one time.

User OCJP
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Answer: A) y = 96,

The maximum number of moose the forest can sustain at one time.

Explanation:

The horizontal asymptote (H.A.) is the value of y that the graph cannot cross.

Since the degree of the numerator equals the degree of the denominator, divide their coefficients to find the H.A.


y=(60)/(0.625)\\\\\\\large\boxed{y=96}

User Dhiraj Sharma
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