Question

The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of 2.94 kg of this oil from 23 °C to 191 °C?

Answer 1

`\boxed{\text{864 kJ}}`

Step-by-step explanation:

The formula for the heat transferred to or from an object is

q = mCΔT

Data:

m = 2.94 kg

C = 1.75 J·°C⁻¹g⁻¹

T₁ = 23 °C

T₂ = 191 °C

Calculations:

(a) Convert the mass to grams

m = 2.94 kg = 2940 g

(b) Calculate ΔT

ΔT = T₂ - T₁ = 191 – 23 = 168 °C

(c) Calculate q

q = 2940 × 1.75 × 168 = 864 000 J = 864 kJ

You must provide
`\boxed{\textbf{864 kJ}}`.