Question

Find an equation for the nth term of the arithmetic sequence.

a19 = -92, a20 = 6

a. an = -1856 + 98(n - 1)
b. an = -1856 - 98(n - 1)
c. an = -1856 - 98(n + 1)
d. an = -1856 + 98(n + 1)

Answer 1

d = 92+6 = 98

an = a1 + 98 (n-1)

a1=a19-98 (n-1)

a1=-92 -98 * 18

=-1856

It’s A ( an = -1856+98(n-1) )