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A car leave P and drives 3km North to Q. From Q it's drives 15km on a bearing North 45degree East to R. Find the distance and bearing of R from P

User Functino
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1 Answer

3 votes

Answer:

17.25 km N37.9°E

Explanation:

The way to solve this is to determine the vertical and horizontal distances traveled.

The bearing means 45° east of north.

Vertically, the car travels a distance of:

y = 3 + 15 cos 45°

y = 3 + 7.5√2

y ≈ 13.6

Horizontally, the car travels a distance of:

x = 15 sin 45°

x = 7.5√2

x ≈ 10.6

The total distance we find with Pythagorean theorem:

d = √(x² + y²)

d = √(10.6² + 13.6²)

d ≈ 17.25

The bearing from north we find with tangent:

tan θ = x / y

tan θ = 10.6 / 13.6

θ ≈ 37.9°

User Ggurov
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