So what I would do is plug in the point into each system:
#1:
y > 0 (-3,0) since y = 0, plug in 0 for y
0 > 0 This can't be true because they are = to each other, so you would need to have a sign of either ≤ or ≥ (less/greater than or equal to) for the point to be a solution to the system
#2 is the same "0 < 0" can't be true
#3
0 ≤ 0 this is true
y > x + 9 Plug in the point (-3,0)
0 > -3 + 9 Simplify
0 > 6 This is false because 0 is not greater than 6
#4
0 ≥ 0 This is true
0 < -3 + 9
0 < 6 This is true because 0 is less than 6
----> 4th option is your answer