Question

What is the length of the magnitude of the vector (-3,2)

Answer 1

`√(13)`

Explanation:

Given the vector < a, b > then the magnitude is

`√(a^2+b^2)`, thus

| (- 3, 2) | =
`√((-3)^2+2^2)` =
`√(9+4)` =
`√(13)`

Answer 2

The length of the magnitude of the given vector <-3,2> is:

`√(13)`

Explanation:

We know that for any vector of the type: <a,b>

The magnitude of the length of the vector is given by the formula:

`|<a,b>|=√(a^2+b^2)`
`√(13)`

Here we are given the vector as: <-3,2>

i.e. a= -3

and b=2.

This means that the length of the magnotude of the vector is given by:

`|<-3,2>|=√((-3)^2+(2)^2)\\\\i.e.\\\\|<-3,2>|=√(9+4)\\\\i.e.\\\\|<-3,2>|=√(13)`

Hence, the answer is:
`√(13)`