Question

Given ax^+bx+c=2(1.2x+0.3)(x-0.5)+(0.5x^+2.5x-1.3). What are the values of a,b, and c?

Answer 1

For this case we must find the values a, b, c:

`2 (1.2x + 0.3) (x-0.5) + (0.5x ^ 2 + 2.5x-1.3) =\\(2.4x + 0.6) (x-0.5) + (0.5x ^ 2 + 2.5x-1.3) =`

We apply distributive property:

`(2.4x ^ 2-1.2x + 0.6x-0.3) + (0.5x ^ 2 + 2.5x-1.3) =\\(2.4x ^ 2-0.6x-0.3) + (0.5x ^ 2 + 2.5x-1.3) =`

We finish the term:

`2.9x ^ 2 + 1.9x-1.6`

Answer:
`a = 2.9\\b = 1.9\\c = -1.6`