Question

The length of a rectangle is 6cm longer than its width.

if the perimeter of the rectangle is 32cm, find its area.

Answer 1

A = 55 cm²

Explanation:

Here, L = W + 6 cm, and P = 2W + 2L = 2W + 2(W + 6 cm) = 32 cm

Then 2W + 2(W + 6 cm) = 32 cm becomes:

2W + 2W + 12 cm = 32 cm, or

4W = 20 cm.

Therefore, W = 20 cm / 4 = 5 cm

The area of this rectangle is A = L · W = (5 cm + 6 cm) · (5 cm), or

A = (11 cm)(5 cm), or A = 55 cm²

Answer 2

A=55

Explanation:

6+x=32

2x+2y=32

2x+2(6+x)=32

4x=20

x=5

and then y=6+5=11

A=x*y11*5=55