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While training for a marathon, Jeff wants to increase the number of miles he runs each day. On the first day of training, Jeff runs 5 miles. He plans on increasing the number of miles he runs a day by 1 for the remainder of the week. Write a series to model the situation.

Also the series doesn't have to be more than seven numbers*****

User Abarax
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2 Answers

7 votes

Answer:

the next answer is arithmetic, and then 56 miles

Explanation:

I just did on edge :)

User Bill Frasure
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8.1k points
4 votes

Answer:

The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

Explanation:

* Lets revise the arithmetic series

- In the arithmetic series there is a constant difference between

each two consecutive numbers

- Ex:

# 2 , 5 , 8 , 11 , ………………………. (constant difference is 3)

# 5 , 10 , 15 , 20 , ………………………… (constant difference is 5)

# 12 , 10 , 8 , 6 , …………………………… (constant difference is -2)

* General term (nth term) of an Arithmetic series:

- If the first term is a and the common diffidence is d, then

U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , U5 = a + 4d

- So the nth term is Un = a + (n – 1)d, where n is the position of the

number in the series

* Lets solve the problem

- Jeff wants to increase the number of miles he runs each day

∴ He will add the initial value by constant number each day

- He plans on increasing the number of miles he runs a day by 1

∴ The constant value is 1 mile

- On the first day of training, Jeff runs 5 miles

∴ The first value is 5 miles

∴ The series is arithmetic

∵ a = 5 , d = 1

- He do that for the remainder of the week

∵ The week has 7 days

∴ The series has 7 terms

∵ The rule of the series is Un = a + (n - 1)d

∵ a = 5 and d = 1

∴ Un = 5 + (n - 1)(1)

∴ Un = 5 + n - 1

∴ Un = 4 + n ⇒ n is the position of the number

- Substitute n from 1 to 7 to find the series

∴ The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

User Rmsys
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