Question

9.two ropes tied to a tree branch hold up a child swing as shown in figure 7 . the tension in each rope is 2.28N.what is the combined force (magnitude and direction) of the two ropes one the swing?

(please answer fast important)

Answer 1

Step-by-step explanation:

The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Given data :

Tension in the ropes ( T ) = 2.28 N

Angle made by ropes = 13° vertical

Determine the combined force of the two ropes

F ( combined force ) = T + T

= 2.28 + 2.28 = 4.56 N

from the question 13° vertical is approximately equal to 77° above the positive X-axis.

Therefore the combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.

Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Answer 2

The combined force of the two ropes on the swing is 4.56 N, acting at an angle of 13 degrees above the horizontal.

Here's how we can find that:

1. **Resolve the forces of each rope into their horizontal and vertical components.** Since the ropes are symmetrical, each rope's horizontal component will cancel out. The vertical component of each rope will be 2.28 N * cos(13 degrees).

2. **Sum the vertical components of the two ropes.** This will give you the total vertical force acting on the swing, which is 2 * 2.28 N * cos(13 degrees) ≈ 4.56 N.

3. **The direction of the combined force is the same as the direction of the total vertical force.** This means the combined force is acting upwards at an angle of 13 degrees above the horizontal.

Therefore, the combined force of the two ropes on the swing is 4.56 N, acting at an angle of 13 degrees above the horizontal.