Question

Can someone help me??!!!!!

Answer 1

III quadrant

Step-by-step explanation:

First of all, let's write the components of each vector along the two directions. We have:

`B_x = B cos 33^\circ = (5.6) cos 33^\circ=-4.7\\B_y = B sin 33^\circ = (5.6) sin 33^\circ=-3.0`

where we put a negative sign on both components, since they are in the negative x- and y- direction.

Similarly,

`C_x = C sin 22^\circ = (4.8) sin 22^\circ=1.8\\C_y = C cos 22^\circ = (4.8) cos 22^\circ=-4.5`

where we put a negative sign on the y-direction, since it is along the negative direction.

Now we sum the components along each axis:

`B_x + C_x = -4.7+1.8=-2.9\\B_y + C_y = -3.0 + (-4.5)=-7.5`

We see that both components of (B+C) are negative, so this vector must be in the 3rd quadrant.