Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

If s(x) = 2x^2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

Answer 1

A) 2x³+11x²+8x-16

Explanation:

When you multiply s(x) by t(x) you get something like this:

`s(x) * t(x) = (2 {x}^(2) + 3x - 4) * (x + 4) \\ = 2 {x}^(3) + 3 {x}^(2) - 4x + 8 {x}^(2) + 12x - 16 \\ = 2 {x}^(3) + 11 {x}^(2) + 8x - 16`

Answer 2

Answer: A) 2x³ + 11x² + 8x - 16

Explanation:

s(x) · t(x) = (x + 4)(2x² + 3x - 4)

= x(2x² + 3x - 4) + 4(2x² + 3x - 4)

= 2x³ + 3x² - 4x + 8x² + 12x - 16

= 2x³ + (3x² + 8x²) + (- 4x + 12x) - 16

= 2x³ + 11x² + 8x - 16