Question

The number of instructions N performed per second by a computer varies directly as the speed S of the​ computer's internal processor. A processor with a speed of 20 megahertz can perform 1 comma 600 comma 000 instructions per second.

​a) Find an equation of variation.

​b) How many instructions per second will the same processor perform if it is running at a speed of 180 ​megahertz?

Answer 1

a)

The equation of variation is;

N = 80000*S

b)

14400000

Explanation:

We are informed that the number of instructions N performed per second by a computer varies directly as the speed S of the​ computer's internal processor. This means that N and S are directly proportional;

N∝S

Introducing a constant of proportionality, k;

N=k*S

We shall find the value of k by using the information given;

N = 1600000

S = 20

k = 1600000/20

= 80000

a)

The equation of variation is thus;

N = 80000*S

b)

We are required to find N when S = 180

Using the equation of variation obtained above;

N = 80000 (180)

= 14400000