Question

A car is traveling at vx = 36 m/s. the driver applies the brakes and the car decelerates at ax = -6. 0 m/s2. what is the stopping distance?

Answer 1

6 Meters

Explanation:

If the car is driving at a constant velocity of 36 m/s and accelerates at -6.0 m/s ^2 to a stop, then the distance of the car decelerates to a stop in 6 seconds.

a=v/t ->>> 6= 36/t