Question

two appliances a lamp with a resistance of 15 and a curling iron with a resistance of 20 are connected in parallel to a 120v source through a 2 resistor in series how much current passes through the circuit when both appliances are on?

Answer 1

11.3 A

Step-by-step explanation:

First of all, we need to find the equivalent resistance of the two appliances in parallel, which is given by:

`(1)/(R_(12))=(1)/(R_1)+(1)/(R_2)=(1)/(15 \Omega)+(1)/(20 \Omega)=0.116 \Omega^(-1)\\R_(12) = 8.6 \Omega`

Then we know that these two appliances are connected in series to another resistor of

`R_3 = 2 \Omega`

So the total resistance of the circuit is

`R=R_(12)+R_3 = 8.6\Omega + 2\Omega = 10.6\Omega`

And since we know the voltage of the source,

V = 120 V

We can now calculate the current in the circuit by using Ohm's law:

`I=(V)/(R)=(120 V)/(10.6 \Omega)=11.3 A`