Question

Please help me out :)

Answer 1

`(√(17) )/(7)`

Explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx =
`√(1-cos^2x)`

Note that (
`(4√(2) )/(7)`)² =
`(32)/(49)`

sinΘ =
`√(1-(32/49))`

=
`\sqrt{(17)/(49) }` =
`(√(17) )/(7)`