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If tanØ = 3/4, Find sinØ

a. SinØ=1/2

b. sinØ = 3/5

c. sinØ = 2

d sin Ø = 8/5

User Raju
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1 Answer

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Answer: This is some information I have gathered to help you since I cannot answer this directly sin θ + (cot θ)(cos θ)

= sin θ + (cos θ / sin θ)(cos θ)

= sin θ + cos² θ / sin θ

Since cos² θ = 1 - sin² θ,

= sin θ + (1 - sin² θ) / sin θ

= sin θ + 1 / sin θ - sin θ

= 1 / sin θ

= csc θ ∎ Sin(x) = tan(x) / [sqrt(1 + tan^2(x)]

Sin(theta) =3/4 / sqrt[1 + .75^2]

Sin(theta) =0.75 / sqrt[ 1.5625 ]

Sin(theta) =0.75 / 1.25

Sin(theta) = 0.60

User Evets
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