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Chemistry help??

A student increases the temperature of a 100 cm3 balloon from 60°C to 120°C. What will the new volume of the balloon be? (Be careful with units.)



(a) 118 cm3


(b) 200 cm3


(c) 236 cm3


(d) 400 cm3

1 Answer

7 votes

Final answer:

OPTION A.

Using Charles's Law, the temperature of the balloon is converted to Kelvin and the law is applied to find the new volume when the temperature is increased from 60°C to 120°C. The new volume is approximately 118 cm³.

Step-by-step explanation:

The question involves applying Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is constant. To find the new volume after an increase in temperature, we convert the temperatures from Celsius to Kelvin by adding 273. The initial temperature (T1) is thus 60°C + 273 = 333K and the final temperature (T2) is 120°C + 273 = 393K. The initial volume (V1) is 100 cm³.

Charles's Law is given by the formula V1/T1 = V2/T2, where V2 is the final volume. Applying this formula, we get:

V1/T1 = V2/T2
(100 cm³) / (333K) = V2 / (393K)

Multiplying both sides by 393K, we find the final volume V2:

V2 = (100 cm³) * (393K) / (333K)

This results in:

V2 ≈ 118 cm³

Therefore, the new volume of the balloon, after increasing the temperature from 60°C to 120°C, will be approximately 118 cm³.

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