Answer:
(a) Rectangle 1 and rectangle 2 are similar
(b) The perimeter of Rectangle 2 is k times the perimeter of Rectangle 1
(c) The area of Rectangle 2 is k² times the area of Rectangle 1
Explanation:
* Lets talk about the similarity
- Two rectangles are similar if there is a constant ratio between
their corresponding sides
- Rectangle 1 has dimensions x and y
- Rectangle 2 has dimensions kx and ky
- The ratio between their dimensions is:
kx/x = k and ky/y = k, so there is a constant ratio K between their
corresponding dimensions
(a) Rectangle 1 and rectangle 2 are similar
- The perimeter of any rectangle is 2(the sum of its two dimensions)
∵ Rectangle 1 has dimensions x and y
∴ Its perimeter = 2(x + y) = 2x + 2y ⇒ (1)
∵ Rectangle 2 has dimensions kx and ky
∴ Its perimeter = 2(kx + ky) = 2kx + 2ky
- By taking k as a common factor
∴ Its perimeter = k(2x + 2y) ⇒ (2)
- From (1) and (2)
∵ The perimeter of rectangle 1 = (2x + 2y)
∵ The perimeter of rectangle 2 = k(2x + 2y)
∴ The perimeter of rectangle 2 is k times the perimeter of rectangle 1
(b) The perimeter of Rectangle 2 is k times the perimeter of Rectangle 1
- The area of any rectangle is the product of its two dimensions
∵ Rectangle 1 has dimensions x and y
∴ Its area = x × y = xy ⇒ (1)
∵ Rectangle 2 has dimensions kx and ky
∴ Its area = kx × ky = k²xy ⇒ (2)
- From (1) and (2)
∵ The area of rectangle 1 = xy
∵ The area of rectangle 2 = k²xy
∴ The area of rectangle 2 is k² times the area of rectangle 1
(c) The area of Rectangle 2 is k² times the area of Rectangle 1