Question

BC is tangent to circle A at point B. What is m2ACB if mZCAB = 22° ?
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Answer 1

68°

Explanation:

We know that sum of 3 angles in a triangle is 180°.

In ΔBAC, there are angles B, A, and C. Thus we can say:

B + A + C = 180

Since, BC is tangent to circle, the point of tangency, B is a 90 degree angle. So angle B is 90.

Also, given angle CAB is 22, which, in other word, is angle A is 22.

Thus, we can write:

B + A + C = 180

90 + 22 + C = 180

112 + C = 180

C = 180 - 112 = 68

Measure of angle ACB = 68°