206k views
1 vote
Find the limit of the function algebraically. limit as x approaches zero of quantity x cubed plus one divided by x to the fifth power.

User Ibnetariq
by
7.0k points

1 Answer

3 votes

Answer:


\displaystyle \lim_(x \to 0) \Big( x^3 + (1)/(x^5) \Big) = \text{und} \text{efined}

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
\displaystyle \lim_(x \to c) x = c

Explanation:

Step 1: Define

Identify


\displaystyle \lim_(x \to 0) \Big( x^3 + (1)/(x^5) \Big)

Step 2: Evaluate

  1. Limit Rule [Variable Direct Substitution]:
    \displaystyle \lim_(x \to 0) \Big( x^3 + (1)/(x^5) \Big) = 0^3 + (1)/(0^5)
  2. Simplify:
    \displaystyle \lim_(x \to 0) \Big( x^3 + (1)/(x^5) \Big) = \text{und} \text{efined}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

User Beric
by
6.6k points