Answer:
The solution is
![(3, -2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/86nrakbrie391ld5u3e5wpchvqzha9glix.png)
Explanation:
We have the following system of equations
Equation 1)
![d + e = 1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qjoj5oclstzu1n1nd3k3ives9ivr9re24v.png)
Equation 2)
![-d + e = -5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/557huknru5wk1lorsi85xan19237pnifss.png)
To solve the system of equations add equation 1 with equation 2 and solve for variable e.
![d + e = 1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qjoj5oclstzu1n1nd3k3ives9ivr9re24v.png)
+
![-d + e = -5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/557huknru5wk1lorsi85xan19237pnifss.png)
--------------------------
![0d + 2e = -4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5tnolnx3e059onsjapcn0w76e1g9yrnu45.png)
![e = -2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rj0osjp05cdan31exzvys28iwi56g1v7w2.png)
Now substitute the value of e in equation 1 or equation 2 and solve for d.
![d + (-2) = 1\\\\d = 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r3cjl392nz60mo2wx0651pecjkas286z46.png)
Therefore the solution of the system is the ordered pair
![(3, -2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/86nrakbrie391ld5u3e5wpchvqzha9glix.png)