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A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?

User Rashon
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2 Answers

4 votes

Answer:

The answer is D. on edgen

Step-by-step explanation:

D. 5.0

User Lesya
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3 votes

Answer: 5 cm

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

The Mirror equation is:


(1)/(f)=(1)/(u)+(1)/(v) (1)

Where:


f=-6cm is the focal distance


u=12cm is the distance between the object and the mirror


v is the distance between the image and the mirror

We already know the values of
f and
u, let's find
v from (1):


v=(u.f)/(u-f) (2)


v=((12cm)(-6cm))/(12cm-(-6cm))


v=-4cm (3)

On the other hand, the magnification
m of the image is given by the following equations:


m=-(v)/(u) (4)


m=(h_(i))/(h_(o)) (5)

Where:


h_(i) is the image height


h_(o)=15cm is the object height

Now, if we want to find the image height, we firstlu have to find
m from (4), substitute it on (5) and find
h_(i):

Substituting (3) in (4):


m=-(-4cm)/(12cm)


m=(1)/(3) (6)

Substituting (6) in (5):


(1)/(3)=(h_(i))/(15cm)


h_(i)=(15cm)/(3)

Finally we obtain the value of the height of the image produced by the mirror:


h_(i)=5cm

User Ahmed HENTETI
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