Question

Y= -3(x-3)^2+4 identify the axis of symmetry.

Answer 1

The equation of the axis of symmetry is x = 3

Explanation:

Perform the indicated mult., obtaining:

y = 3(x² - 6x + 9) + 4.

Mult. each term inside parentheses by 3, we get:

y = 3x² - 18x + 27 + 4, or

y + 3x² - 18x + 31

Here the coefficients are a = 3, b = -18 and c = 31.

The axis of symmetry is x = -b / (2a), which here is:

-(-18)

x = ----------- = 18/6 = 3

2(3)

The equation of the axis of symmetry is x = 3

Answer 2

x=3

EXPLANATION

The given function is

`y= -3(x-3)^2+4`

This function is of the form.

`y= a(x-h)^2+k`

This is called the vertex form.

The axis of symmetry is given by

`x = h`

By comparing to

`y= -3(x-3)^2+4`

a=-3, h=3 and k=4

Hence the axis of symmetry is x=3