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What is the sum of 2 / 3x^2 +12x and 8 / c. Need steps

User Asahi
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Answer:


(2c)/(3x^2c)+ (36x^3c)/(3x^2c) +(24x^2)/(3x^2c) [\tex]</p><p><strong>Step-by-step explanation:</strong></p><p>We need to find sum of 2 / 3x^2 +12x and 8 / c</p><p>So, solving:</p><p>[tex]((2)/(3x^2) + 12 x ) +(8)/(c)

Taking LCM of 3x^2 and 1 i.e. 3x^2


=((2 + 12 x(3x^2))/(3x^2) ) +(8)/(c)\\=((2 + 36x^3)/(3x^2) ) +(8)/(c)\\=(2 + 36x^3)/(3x^2) +(8)/(c)\\LCM \,\, 36x^2 c\\=((2 + 36x^3)c + 8(3x^2))/(3x^2c)\\=(2c + 36x^3c + 24x^2)/(3x^2c)\\= (2c)/(3x^2c)+ (36x^3c)/(3x^2c) +(24x^2)/(3x^2c)

User Randhir Yadav
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