Question

A sample of carbon dioxide occupies 200 L at 22°C and 1.0 atm. At what temperature will

it expand to 1000 L at 0.90 atm?

Answer 1

1328 K or 1055 °C

Step-by-step explanation:

To find the new temperature, you need to use the Combined Gas Law:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. After converting the temperature (T₁) from Celsius to Kelvin, you can plug the values into the equation and simplify.

P₁ = 1.0 atm P₂ = 0.90 atm

V₁ = 200 L V₂ = 1000 L

T₁ = 22 °C + 273.15 = 295.15 K T₂ = ? K

P₁V₁ / T₁ = P₂V₂ / T₂

(1.0 atm)(200 L) / 295.15 K = (0.90 atm)(1000 L) / T₂

0.6776 = (0.90 atm)(1000 L) / T₂

(0.6776) x T₂ = (0.90 atm)(1000 L)

(0.6776) x T₂ = 900

T₂ = 1328 K

T₂ = 1055 °C