Answer:
The radius of circle is 5 cm
Explanation:
Given a right triangle △ABC with right angle C is inscribed in a circle in which
m∠C = 90°, AC = 8 cm, BC = 6 cm
we have to find the radius of circle.
As ACB is right angles triangle where angle C is right angle.
⇒ side AB must be the diameter of circle as angle made at semi circle is 90°

By Pythagoras theorem




Hence, the radius of circle is 5 cm