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If <ACD <BCD which of the following relationships can be proved and
why?


If <ACD <BCD which of the following relationships can be proved and why? ​-example-1
User Amro
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2 Answers

5 votes

Answer:C

Explanation:

User Daniel Becker
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3 votes

Answer:

Option C.

Explanation:

we know that

The Angle-Side-Angle (ASA) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

In this problem

The included side is the side CD and the angle ∠ACD and ∠ADC of triangle ACD are congruent with angle ∠BCD and ∠CDB of triangle BCD

therefore

Triangles ACD and BCD are congruent by ASA

User Igor Zilberman
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