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Compare the three functions below. Which has a greater period? A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)

User Idik
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1 Answer

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Explanation:

Given functions are

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)

or we can rewrite :

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=(4.3)cos(2x+4)

We need to find their periods which is basically (2pi/coefficient of x) of the given cosine function.

So the period of given choices are:

A)
(2\pi)/(2), B)
(2\pi)/(4), and C)
(2\pi)/(2)

or

A)
\pi, B)
(\pi)/(2), and C)
\pi

Greatest of them is
\pi

So the correct choice is A) y = 3cos(2x+1) and C) y=cos(2x+4) (4.3)

User Elimariaaa
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