Answer:
A. 48.35°, 94.94°, 36.71°
Explanation:
Given,
ABC is a triangle,
In which AB = 12 miles, BC = 15 miles and AC = 20 miles,
By the cosine law,



Similarly,


By substituting the values in equation (1),


Similarly, from equation (2) and (3),


Hence, Option 'A' is correct.