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What is the standard form of an ellipse with foci at (0, ±2), and vertices at (0, ±4)?

What is the standard form of an ellipse with foci at (0, ±2), and vertices at (0, ±4)?-example-1

1 Answer

4 votes

Answer:

B) x^2/12 +y^2/16 = 1

Explanation:

The distance from focus to covertex is the same as the distance from the center to the vertex: 4. So, the Pythagorean theorem tells you ...

a^2 + 2^2 = b^2

a^2 +4 = 4^2 = 16

a^2 = 16 -4 = 12

So, the standard-form equation ...

x^2/a^2 +y^2/b^2 = 1

looks like this when the values are filled in:

x^2/12 +y^2/16 = 1

User Rahul Jangra
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