Answer:
Explanation:
1st use the two points to find the slope of the line that passes thru those two points
m = y2 - y1 / x2 - x1
where point1 = ( x1, y1 ) and point2 = (x2, y2 )
your are given P1 = ( -2,10) and P2 = (1,1)
find the slope
m = 1-(-2) / 1-10
m = 1+2 / -9
m = 3 / -9
m = - 1/3
then use the point-slope formula [y-y1 = m(x-x1)] with either of the two points, I'll use P2 b/c it seems easier (1,1) , you get the same results with either point and work the problem to the slope-intercept form [y = mx +b ]
y -y1 = m(x-x1)
y-1 = -1/3(x-1)
y-1 = -1/3x + 1/3
y = -1/3x + 1/3 + 1
y = -1/3x + 4/3
:) got it ?