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Pablo ran a concession stand last Saturday and made $79.80 from selling a total of 53 hot dogs and hamburgers. Each hot dog sold for $1.40 and each hamburger sold for $1.80. Which system of equations can be used to determine the number of hot dogs, x, and hamburgers, y, that were sold?

A. 1.4x + 1.8y = 79.8
39x + 14y = 53

B. 0.7x + 0.9y = 79.8
x + y = 3.2

C. 1.4x + 1.8y = 79.8
x + y = 53

D. 2.8x + 3.6y = 3.2
x + y = 546

User Cozimetzer
by
8.5k points

1 Answer

3 votes

Answer:

C. 1.4x + 1.8y = 79.8

x + y = 53

Explanation:

The problem statement gives rise to two equations, one for the amount of money made, and one for the number of items sold. If x and y represent the numbers of items, and if 53 items were sold, then one of the equations will be ...

x + y = 53

This is sufficient to let you choose the correct answer.

___

Since "x" items were sold for $1.40 and "y" items were sold for $1.80, the sales revenue will be the sum of products of price and quantity:

1.40x +1.80y = 79.80

This confirms the choice of answer.

User Mohamed Nuur
by
8.2k points
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