Question

The period of this function is

2π

π/8

π/4

π/2

Answer 1

I’m not quite sure what the function is but if it’s sine the period is pi/8

Answer 2

The period is

`(\pi)/(8)`

Step-by-step explanation

The given function completes four cycles on the interval

`</p><p>[ - (\pi)/(4) , (\pi)/(4) ]`

Therefore the period is

`= ( (\pi)/(4) - (\pi)/(4) )/(4)`

Simplify the numerator:

`= ( (\pi)/(2))/(4)`

Simplify further to get:

`= (\pi)/(8)`