Answer:
![\lim_(x \to \infty) (2500+17(x-100))/(x)=17](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jmx038071357ie96516aiiw43ilktyx6gh.png)
Explanation:
Let the theme park sold number of tickets = x
Theme park charges $500 for group booking more than 25 tickets.
In addition to this theme park charges $20 per ticket for up to 100 tickets.
So charges of 100 tickets = 500 + (100×20) = $2500
For more than 100 tickets theme park charges $17, so charges for x tickets will be = 500 + (100×20) + 17(x - 100)
= 2500 + 17(x - 100)
Cost of one ticket of the theme park =
![(2500+17(x-100))/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wmsk6c29b4a2secron1ahtxd0gw743t34i.png)
Now we have to write the limit equation when number of tickets purchased becomes very high.
![\lim_(x \to \infty) (2500+17(x-100))/(x)=17](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jmx038071357ie96516aiiw43ilktyx6gh.png)
[By solving limit as below
![\lim_(x \to \infty) (2500+17(x-100))/(x)= \lim_(x \to \infty)(2500)/(x)+17-(1700)/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u5169nrefh4thr6n62we6ln1j3a79mnv0b.png)
since
![\lim_(x \to \infty)((1)/(x))=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n2edi52tpdkdl6hmama6o9kmlbzger3gnm.png)
Therefore,
![\lim_(x \to \infty)(2500)/(x)+17-(1700)/(x)=0+17-0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ydbrqi8jem47cxxnqu4mgqoefy5l3viy3l.png)
= 17 ]