Question

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

y – 9 = –6(x – 3)
y + 9 = –6(x + 3)
y – 3 = –6(x – 9)
y + 3 = –6(x + 9)

Answer 1

y+3= -6(x+9) is the answer

Explanation:

Answer 2

`y+3=-6(x+9)`

Explanation:

We are given that

Slope of a line=-6

Given point =(-9,-3)

We have to find the equation which represents the line.

The equation of line passing through the given point
`(x_1,y_1)` with slope m is given by

`y-y_1=m(x-x_1)`

Substitute the values then we get

The equation of line passing through the point (-9,-3) with slope -6 is given by

`y-(-3)=-6(x-(-9))`

`y+3=-6(x+9)`

Hence, the equation of line that passes through (-9,-3) and has a slope -6 is given by

`y+3=-6(x+9)`