Question

A student boils 9.43 grams of an unknown substance into vapor. If completely vaporizing the substance required 8,720 joules of energy, what is the heat of vaporization? The heat of vaporization is joules/gram.

Answer 1

Heat of vapourrisation required to( change the state) of water is 2260 J/grm.

Answer 2

Answer : The heat of vaporization is, 924.7 joules/gram.

Explanation :

Formula used for heat of vaporization :

`H_(Vap)=(q)/(m)`

where,

`H_(Vap)` = heat of vaporization = ?

q = required heat = 8720 J

m = mass of substance = 9.43 g

Now put all the given values in the above formula, we get :

`H_(Vap)=(8720J)/(9.43g)=924.7J/g`

Therefore, the heat of vaporization is, 924.7 joules/gram.