Question

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution

Answer 1

16 Molarity

Step-by-step:

M= mols/L

M= 8mols/.5L

M= 16 Molarity

Answer 2

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

Step-by-step explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

`Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}* Volume (L)}`

Moles of NaOH = 8 moles

Volume of the solution = 0.5 L

`Molarity=(8 mol)/(0.5 L)=16.0 M`

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.