Question

If I need to find 4 consecutive integers and the second and fourth equal 58 how do I find the first and third integers?

Answer 1

27, 29

Explanation:

n, n + 1, n + 2, n + 3 - four consecutive integers

The equation:

(n + 1) + (n + 3) = 58

n + 1 + n + 3 = 58 combine like terms

(n + n) + (1 + 3) = 58

2n + 4 = 58 subtract 4 from both sides

2n = 54 divide both sides by 2

n = 27 - first

n + 1 = 28 - second

n + 2 = 29 - third

n + 3 = 30 - fourth

Answer 2

Answer: 27, 29

Explanation:

Consecutive integers are as follows:

First Integer: x

Second Integer: x + 1

Third Integer: x + 2

Fourth Integer: x + 3

The second and fourth = 58

x + 1 + x + 3 = 58

2x + 4 = 58

2x = 54

x = 27

First Integer: x = 27

Third Integer: x + 2 = 27 + 2 = 29