Question

Please help with the verifying.

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Answer 1

• let's solve each trigonometric function alone
• csc^2(x)=1/sin^2(x)
• tan^2(x)=sin^2(x)/cos^2(x)
• if we divide them the result will be=cot^2(x)(and that's the R.H.S)
• cot^2(x)=cos^2(x)/sin^2(x)
• and then divide it by sin^2(x)the result will also be =cot^2(x) (and that's the L.H.S)
• R.H.S=L.H.S