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Question 18 of 25

2 Points
How many solutions does the following system of equations have
2v=5x+4
v=3.x + 2
OA. Two
O B. Zero
c. Infinitely many
d. one


User Arjit
by
8.5k points

1 Answer

4 votes

Answer:

the ONE solution is (0, 2) (Answer D)

Explanation:

Please fix up the formatting a bit:

2v=5x+4

v=3.x + 2

becomes:

2v = 5x + 4

v = 3x + 2

Multiplying all terms of the 2nd equation by -2, we get:

-2(v = 3x + 2), or -2v = -6x - 4

Combining this result with the first equation, we get:

2v = 5x + 4

-2v = -6x - 4

--------------------

0 = -x + 0

Then x must = 0. Subbing this x value into the 2nd equation, we get:

v = 3(0) + 2. Thus, v = 0, and the ONE solution is (0, 2).

User Dfrojas
by
8.2k points

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