Question

If a sample of a gas has an initial volume of 15 L and a pressure of 125 kPa what will the pressure of the gas be (in atm) if the volume is increased to 29 L?

Answer 1

apply Boyle's law

Boyle's Law, an ideal gas law which states that the volume of an ideal gas is inversely proportional to its absolute pressure at a constant temperature

V = 1/P

PV = 1

PV= constant

let 15L = V1 and 125kPa = P1

9L =V2 and P2 = ?

Now from Boyle's law

P1V1 = P2V2

Substitute the values

15L * 125kPa = 29 * P2

P2 = 64.65kPa

convert Pascal's into atm

1 pascal =

9.869 × 10-6 atmosphere

P2 = 64.65 *10^3 *9.869 × 10-6 (kPa is kilo Pascal's)