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Use the divergence theorem to evaluate the integral i = z z ∂w f · ds when f(x, y, z) = y i − 4yz j + 3z 2 k and ∂w is the boundary of the solid w enclosed by the upper half of the sphere

User Hopstream
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1 Answer

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\vec f(x,y,z)=y\,\vec\imath-4yz\,\vec\jmath+3z^2\,\vec k


\implies\\abla\cdot\vec f(x,y,z)=0-4z+6z=2z

By the divergence theorem,


\displaystyle\iint_(\partial W)\vec f\cdot\mathrm d\vec S=\iiint_W2z\,\mathrm dV

I'll assume a sphere of radius
r centered at the origin, and that
W is bounded below by the plane
z=0. Convert to spherical coordinates, taking


x=\rho\cos\theta\sin\varphi


y=\rho\sin\theta\sin\varphi


z=\rho\cos\varphi

Then


\displaystyle\iiint_W2z\,\mathrm dV=\int_0^(\pi/2)\int_0^(2\pi)\int_0^r2\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\pi r^4

User Seyed Mohammad
by
7.1k points
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