Question

Find the number of real number solutions for the equation. x^2+0x-1=0

Answer 1

+1

-1

Explanation:

Given equation :

`x^(2) +0x-1` = 0

`x^(2) -1 = 0\\x^(2) =1\\x=√(1)`

x= ±1

x= 1 and x= -1

±1 lies in solution set of real numbers !