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Triangle Angle Sum Theorem

Triangle Angle Sum Theorem-example-1
User Sklero Mc
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2 Answers

13 votes
13 votes


\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

Given:


\longrightarrow \sf{KED = 100^\circ}


\longrightarrow \sf{\angle ECD = 60^\circ}


\leadsto According to the triangle angle sum theorem, the sum of interior angles of a triangle is 180°.


\leadsto We can find the value of ∠E if we know the sum of two supplementary angles is equal to 180°


\longrightarrow \sf{m \angle E+ m \angle K=180^\circ}


\longrightarrow \sf{m \angle E+ 100^\circ =180^\circ}


\longrightarrow \sf{m \angle E= 80^\circ}

As we find the value of ∠E, we can replace it in the initial formula.
\downarrow


\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}


\bm{m \angle C + m \angle \boxed{\bm D} = m \angle \boxed{\bm E}}


\bm{m \angle D= \boxed{\bm{ 40^\circ}}}

User Dylan Reich
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2.6k points
18 votes
18 votes

Answer:

Explanation:

Comment

The sum of the remote interior angles = The exterior angle not connected to them

What that means is that

<C + <D = <KEB

Givens

<C = 60

<KED = <C + <D

Solution and answer

<KED = <C + <D Substitute the givens into this equation

100 = 60 + <D Turn this around

<60 + <D = <100 Answer first equation

Subtract 60 from both sides

<60-<60 + <D = <100 - 60

<D = <40 Answer second Equation

User Tom Bom
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