Question

I need help with the math problem

Answer 1

Part A) The perimeter of the court is
`P=139.25\ ft`

Part B)
`5\ cans`

Explanation:

Part A) we know that

The perimeter of the court is equal to the perimeter of the square plus the perimeter of semicircle

`P=4D+(\pi D )/(2)`

we have that

`D=25\ ft`

substitute

`P=4(25)+((3.14*25))/(2)`

`P=139.25\ ft`

Part B)

Find the area above the foul line (labelled II)

The area of a semicircle is equal to

`A=(\pi r^(2))/(2)`

we have

`r=25/2=12.5\ ft`

substitute

`A=((3.14)(12.5)^(2))/(2)`

`A=245.31\ ft^(2)`

Round to the nearest whole number

`A=245\ ft^(2)`

One can of paint covers 50 square feet of floor

so

Calculate how many cans of blue paint does the school need to purchase

`245/50=4.9\ cans`

Round up

`5\ cans`